Given are the Bézier points of a cubic Bézier curvex(t) with \mathbf{b}_{0}=\left(\begin{array}{l}

0 \\

0

\end{array}\right), \quad \mathbf{b}_{1}=\left(\begin{array}{c}

0 \\

27

\end{array}\right), \quad \mathbf{b}_{2}=\left(\begin{array}{l}

27 \\

27

\end{array}\right), \quad \mathbf{b}_{3}=\left(\begin{array}{c}

27 \\

0

\end{array}\right) Use the de Casteljau algorithm to determine the value x(3) as well as all intermediate points!